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a Is the following reaction a balanced chemical equation for the combustion (reaction with oxygen gas)of glucose, C_(6)H_(12)O_(6), to give carbon dioxide and water? C_(6)H_(12)O_(6)(s)+6O_(2)(g)arrow 6CO_(2)(g)+6H_(2)O(l) Yes No D Is the following reaction a balanced chemical equation for the reaction between xenon tetrafluoride gas and water to give xenon oxygen, and hydrogen fluoride Xef_(4)(g)+2H_(2)O(g)arrow Xe(g)+O_(2)(g)+4HF(g) Yes No

Soru

a Is the following reaction a balanced chemical equation for the combustion (reaction with oxygen gas)of glucose,
C_(6)H_(12)O_(6), to give carbon dioxide and water?
C_(6)H_(12)O_(6)(s)+6O_(2)(g)arrow 6CO_(2)(g)+6H_(2)O(l)
Yes
No
D Is the following reaction a balanced chemical equation for the reaction between xenon tetrafluoride gas and water to give xenon oxygen, and hydrogen fluoride
Xef_(4)(g)+2H_(2)O(g)arrow Xe(g)+O_(2)(g)+4HF(g)
Yes
No

a Is the following reaction a balanced chemical equation for the combustion (reaction with oxygen gas)of glucose, C_(6)H_(12)O_(6), to give carbon dioxide and water? C_(6)H_(12)O_(6)(s)+6O_(2)(g)arrow 6CO_(2)(g)+6H_(2)O(l) Yes No D Is the following reaction a balanced chemical equation for the reaction between xenon tetrafluoride gas and water to give xenon oxygen, and hydrogen fluoride Xef_(4)(g)+2H_(2)O(g)arrow Xe(g)+O_(2)(g)+4HF(g) Yes No

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a) To determine if the given reaction is a balanced chemical equation for the combustion of glucose, we need to check if the number of atoms of each element is the same on both sides of the equation.<br /><br />The given reaction is:<br />$C_{6}H_{12}O_{6}(s)+6O_{2}(g)\rightarrow 6CO_{2}(g)+6H_{2}O(l)$<br /><br />Let's count the number of atoms of each element on both sides:<br /><br />On the left side:<br />- Carbon (C): 6<br />- Hydrogen (H): 12<br />- Oxygen (O): 6 (from $C_{6}H_{12}O_{6}$) + 12 (from $6O_{2}$) = 18<br /><br />On the right side:<br />- Carbon (C): 6 (from $6CO_{2}$)<br />- Hydrogen (H): 12 (from $6H_{2}O$)<br />- Oxygen (O): 12 (from $6CO_{2}$) + 6 (from $6H_{2}O$) = 18<br /><br />Since the number of atoms of each element is the same on both sides, the given reaction is a balanced chemical equation for the combustion of glucose.<br /><br />Answer: Yes<br /><br />b) To determine if the given reaction is a balanced chemical equation for the reaction between xenon tetrafluoride gas and water to give xenon, oxygen, and hydrogen fluoride, we need to check if the number of atoms of each element is the same on both sides of the equation.<br /><br />The given reaction is:<br />$XeF_{4}(g)+2H_{2}O(g)\rightarrow Xe(g)+O_{2}(g)+4HF(g)$<br /><br />Let's count the number of atoms of each element on both sides:<br /><br />On the left side:<br />- Xenon (Xe): 1<br />- Fluorine (F): 4<br />- Hydrogen (H): 4 (from $2H_{2}O$)<br />- Oxygen (O): 2 (from $2H_{2}O$)<br /><br />On the right side:<br />- Xenon (Xe): 1<br />- Fluorine (F): 4 (from $4HF$)<br />- Hydrogen (H): 4 (from $4HF$)<br />- Oxygen (O): 2 (from $O_{2}$)<br /><br />Since the number of atoms of each element is the same on both sides, the given reaction is a balanced chemical equation for the reaction between xenon tetrafluoride gas and water to give xenon, oxygen, and hydrogen fluoride.<br /><br />Answer: Yes
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