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16) The concentration (M) of HCl in a solution prepared by dissolving 5.5 gof HCl in 200 g of C_(2)H_(6)O __ M. The density of the solution is 0.79g/mL A) 21 B) 0.93 C) 0.58 D) 6.0times 10^-4

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16) The concentration (M) of HCl in a solution prepared by dissolving 5.5 gof HCl in 200 g of
C_(2)H_(6)O __ M. The density of the solution is 0.79g/mL
A) 21
B) 0.93
C) 0.58
D) 6.0times 10^-4

16) The concentration (M) of HCl in a solution prepared by dissolving 5.5 gof HCl in 200 g of C_(2)H_(6)O __ M. The density of the solution is 0.79g/mL A) 21 B) 0.93 C) 0.58 D) 6.0times 10^-4

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To find the concentration of HCl in the solution, we need to calculate the number of moles of HCl and divide it by the volume of the solution in liters.<br /><br />Given:<br />- Mass of HCl = 5.5 g<br />- Density of the solution = 0.79 g/mL<br /><br />First, let's calculate the volume of the solution in liters. The density is given in g/mL, so we need to convert it to g/L:<br /><br />Density = 0.79 g/mL = 0.79 g/mL * 1000 mL/L = 790 g/L<br /><br />Now, we can calculate the volume of the solution in liters:<br /><br />Volume = Mass / Density = 200 g / 790 g/L = 0.2532 L<br /><br />Next, let's calculate the number of moles of HCl:<br /><br />Moles of HCl = Mass / Molar mass = 5.5 g / (36.46 g/mol) = 0.151 mol<br /><br />Finally, we can calculate the concentration of HCl in the solution:<br /><br />Concentration = Moles / Volume = 0.151 mol / 0.2532 L = 0.596 M<br /><br />Therefore, the concentration of HCl in the solution is approximately 0.58 M.<br /><br />The correct answer is C) 0.58.
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