Question 5 A.solution of sodium chloride is made by adding 300cm^3 of water to a flask containing 200cm^3 of 0.50moldm^-3 oldm-3 sodium chloride. Whatis the concentration of the resulting solution? 0.05moldm^-3 B 0.1moldm^-3 c 0.2moldm^-3 D 0.3moldm^-3

To find the concentration of the resulting solution, we need to calculate the total amount of sodium chloride in the solution and divide it by the total volume of the solution.<br /><br />Given information:<br />- Initial volume of sodium chloride solution: 200 cm³<br />- Initial concentration of sodium chloride solution: 0.50 mol/dm³<br />- Volume of water added: 300 cm³<br /><br />Step 1: Calculate the total amount of sodium chloride in the initial solution.<br />Amount of sodium chloride = Concentration × Volume<br />Amount of sodium chloride = 0.50 mol/dm³ × 0.2 dm³ = 0.1 mol<br /><br />Step 2: Calculate the total volume of the resulting solution.<br />Total volume = Initial volume + Volume of water added<br />Total volume = 200 cm³ + 300 cm³ = 500 cm³ = 0.5 dm³<br /><br />Step 3: Calculate the concentration of the resulting solution.<br />Concentration = Amount of sodium chloride / Total volume<br />Concentration = 0.1 mol / 0.5 dm³ = 0.2 mol/dm³<br /><br />Therefore, the concentration of the resulting solution is 0.2 mol/dm³.<br /><br />The correct answer is C) 0.2 mol/dm³.