Sleve analysis on a dry soil sample of mass 1000 g showed that 980 g 270 g of soil pass 4.75 mm and 0.075 mm sieve respectively. The LL=40% & PL=18% . The soil classification

Based on the sieve analysis data provided, we can classify the soil according to the Unified Soil Classification System (USCS).<br /><br />Here's the breakdown of the data:<br />- Mass of dry soil sample: 1000 g<br />- Mass of soil passing 4.75 mm sieve: 270 g<br />- Mass of soil passing 0.075 mm sieve: 980 g<br /><br />To classify the soil, we need to calculate the percentage of soil passing each sieve size.<br /><br />1. Calculate the percentage of soil passing the 4.75 mm sieve:<br /> \[<br /> \text{Percentage passing 4.75 mm} = \left( \frac{270 \text{ g}}{1000 \text{ g}} \right) \times 100 = 27\%<br /> \]<br /><br />2. Calculate the percentage of soil passing the 0.075 mm sieve:<br /> \[<br /> \text{Percentage passing 0.075 mm} = \left( \frac{980 \text{ g}}{1000 \text{ g}} \right) \times 100 = 98\%<br /> \]<br /><br />Now, we can use these percentages to classify the soil according to the USCS. The soil is classified based on the percentage of soil passing the 4.75 mm and 0.075 mm sieves.<br /><br />- If the percentage passing the 4.75 mm sieve is less than 5%, the soil is classified as gravel.<br />- If the percentage passing the 4.75 mm sieve is between 5% and 37.5%, the soil is classified as sand.<br />- If the percentage passing the 4.75 mm sieve is between 37.5% and 75%, the soil is classified as silt.<br />- If the percentage passing the 4.75 mm sieve is greater than 75%, the soil is classified as clay.<br /><br />In this case, the percentage passing the 4.75 mm sieve is 27%, which falls within the range for sand. Therefore, the soil is classified as sand.<br /><br />Additionally, the liquid limit (LL) and plastic limit (PL) are given as 40% and 18%, respectively. These values help to further characterize the soil's plasticity.<br /><br />So, the soil classification based on the provided data is **sand**.