Write a complete C/C+C program which would calculate and display the result of the following equation. Y=e^a(a)/(sqrt (a^b)+sin(30))+ln(1000) Notice that, the a value WOULD NOT BE taken from the user and the b value will be taken from the user as an integer input. The a value will be randomly ganerated integer number be bewteen the range of -10 and -100 The program finds the value of Y according to the formula provided below and display the result on the screen as the output (30 pts.)

Here's a C++ program that calculates the value of Y according to the given formula and displays the result on the screen:<br />```cpp<br />#include <iostream><br />#include <cmath><br />#include <ctime><br />#include <cstdlib><br /><br />using namespace std;<br /><br />int main() {<br /> int a, b;<br /> float Y;<br /><br /> // Generate a random integer for 'a' between -10 and -100<br /> srand(time(0));<br /> a = rand() % (-100 - (-10)) + (-10);<br /><br /> // Take user input for 'b' as an integer<br /> cin >> b;<br /><br /> // Calculate the value of Y according to the formula<br /> Y = exp(a) * a / sqrt(pow(a, b) + sin(30)) + log(1000);<br /><br /> // Display the result on the screen<br /> cout << "The value of Y is: " << Y << endl;<br /><br /> return 0;<br />}<br />```<br />This program includes the necessary headers for input/output operations, mathematical functions, and time functions. It generates a random integer for 'a' between -10 and -100 using the `rand()` function and the `srand(time(0))` function to seed the random number generator. The user is prompted to enter the value of 'b' as an integer. The program then calculates the value of Y according to the given formula and displays the result on the screen using the `cout` statement.