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2HI_((g))=H_(2_((g)))+I_(2_((g)))

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2HI_((g))=H_(2_((g)))+I_(2_((g)))

2HI_((g))=H_(2_((g)))+I_(2_((g)))

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The given chemical equation represents the decomposition of hydrogen iodide (HI) into hydrogen gas (H₂) and iodine gas (I₂). This is a type of chemical reaction known as a decomposition reaction, where a single compound breaks down into two or more simpler substances.

In this reaction, two molecules of hydrogen iodide (2HI) decompose to form one molecule each of hydrogen gas (H₂) and iodine gas (I₂). The reaction is balanced, meaning that the number of atoms of each element is the same on both sides of the equation.

The reaction can be represented as:

2HI_{(g)} \rightarrow H_{2_{(g)}} + I_{2_{(g)}}

This equation shows that two moles of hydrogen iodide gas decompose to produce one mole of hydrogen gas and one mole of iodine gas.
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