Given the function h(x)=4x^2 find: a h(2)=4(a^2)=16 b h(-2)=4(-2)^2=16 h((1)/(2)) g(5)=3

To find the value of $h\left(\frac{1}{2}\right)$, we need to substitute $\frac{1}{2}$ into the function $h(x)=4x^{2}$.<br /><br />$h\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right)^{2} = 4\left(\frac{1}{4}\right) = 1$<br /><br />Therefore, the correct answer is $h\left(\frac{1}{2}\right) = 1$.