Find the number of moles in 3.30 gof (NH4)_(2)SO_(4) A. 132.1 mol B. 40.0 mol C. 0.0279 mol D. 0.0250 mol A B C D

To find the number of moles in 3.30 g of \((NH_4)_2SO_4\), we need to follow these steps:<br /><br />1. **Calculate the molar mass of \((NH_4)_2SO_4\)**:<br /> - Nitrogen (N): \(14.01 \, \text{g/mol}\)<br /> - Hydrogen (H): \(1.01 \, \text{g/mol}\)<br /> - Sulfur (S): \(32.07 \, \text{g/mol}\)<br /> - Oxygen (O): \(16.00 \, \text{g/mol}\)<br /><br /> The formula for ammonium sulfate is \((NH_4)_2SO_4\), which means it has:<br /> - 2 nitrogen atoms<br /> - 8 hydrogen atoms<br /> - 1 sulfur atom<br /> - 4 oxygen atoms<br /><br /> So, the molar mass is calculated as follows:<br /> \[<br /> \text{Molar mass of } (NH_4)_2SO_4 = 2 \times 14.01 + 8 \times 1.01 + 32.07 + 4 \times 16.00<br /> \]<br /> \[<br /> = 28.02 + 8.08 + 32.07 + 64.00<br /> \]<br /> \[<br /> = 132.17 \, \text{g/mol}<br /> \]<br /><br />2. **Calculate the number of moles**:<br /> \[<br /> \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}}<br /> \]<br /> \[<br /> = \frac{3.30 \, \text{g}}{132.17 \, \text{g/mol}}<br /> \]<br /> \[<br /> \approx 0.0250 \, \text{mol}<br /> \]<br /><br />Therefore, the number of moles in 3.30 g of \((NH_4)_2SO_4\) is approximately 0.0250 mol.<br /><br />The correct answer is:<br />D. 0.0250 mol