The density of oxygen gas at STP (standard temperature and pressure) is 1.43g/L How many grams of oxygen gas are at STP in 50.0 L of oxygen gas? 35.8 grams 32.0 grams 0.0286 grams 71.5 grams

To determine the mass of oxygen gas in 50.0 L at STP, we can use the given density of oxygen gas and apply the formula for density:<br /><br />\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]<br /><br />Given:<br />- Density of oxygen gas (\(\rho\)) = \(1.43 \, \text{g/L}\)<br />- Volume (V) = \(50.0 \, \text{L}\)<br /><br />We need to find the mass (m). Rearranging the formula to solve for mass:<br /><br />\[ \text{Mass} = \text{Density} \times \text{Volume} \]<br /><br />Substitute the given values into the equation:<br /><br />\[ \text{Mass} = 1.43 \, \text{g/L} \times 50.0 \, \text{L} \]<br /><br />\[ \text{Mass} = 71.5 \, \text{g} \]<br /><br />Therefore, the mass of oxygen gas in 50.0 L at STP is \(71.5 \, \text{grams}\).<br /><br />The correct answer is:<br />\[ 71.5 \, \text{grams} \]