Fluorine has 7 valence electrons. Which element could pair with it in a 1 atom : 1 fluorine ratio? A Mg(2valenceelectrcns) B Al(3valenceelectrons) Zn(2valenceelectrons) D Li(1valenceelectron)

To determine which element could pair with fluorine in a 1:1 ratio, we need to consider the valence electrons and how they can achieve a stable electron configuration.<br /><br />Fluorine has 7 valence electrons and needs 1 more electron to complete its octet (8 valence electrons). Therefore, it will pair with an element that can provide 1 electron.<br /><br />Let's analyze each option:<br /><br />A. Mg (Magnesium) has 2 valence electrons. Magnesium typically loses 2 electrons to achieve a stable configuration, forming \( \text{Mg}^{2+} \). This would not pair in a 1:1 ratio with fluorine.<br /><br />B. Al (Aluminum) has 3 valence electrons. Aluminum typically loses 3 electrons to achieve a stable configuration, forming \( \text{Al}^{3+} \). This would not pair in a 1:1 ratio with fluorine.<br /><br />C. Zn (Zinc) has 2 valence electrons. Zinc typically loses 2 electrons to achieve a stable configuration, forming \( \text{Zn}^{2+} \). This would not pair in a 1:1 ratio with fluorine.<br /><br />D. \( L \) (an element with 1 valence electron) would lose 1 electron to achieve a stable configuration, forming \( \text{L}^{+} \). This would pair perfectly in a 1:1 ratio with fluorine, as fluorine would gain this 1 electron to complete its octet.<br /><br />Therefore, the correct answer is:<br /><br />D. \( L \) (1 valence electron)