A 7.0.kg object is acted on by two forces.One of the forces is 10.0 N acting toward the east. Which of the following forces is the other force if the acceleration of the object is 1.0m/s^2 toward the east? Select one: 9.0 N west 12.0 N east 7.0 N west 3.0 N west 6.0 Neast

To find the other force acting on the object, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.<br /><br />Given:<br />- Mass of the object (m) = 7.0 kg<br />- Force 1 (F1) = 10.0 N acting toward the east<br />- Acceleration (a) = 1.0 m/s^2 toward the east<br /><br />We need to find the other force (F2) acting on the object.<br /><br />According to Newton's second law, the net force (F_net) acting on the object is given by:<br /><br />F_net = m * a<br /><br />Since both forces are acting toward the east, we can consider the east direction as positive. Therefore, the net force can be calculated as:<br /><br />F-net = F1 + F2<br /><br />Substituting the given values:<br /><br />F-net = 7.0 kg * 1.0 m/s^2 = 7.0 N<br /><br />Since F1 = 10.0 N, we can solve for F2:<br /><br />F2 = F-net - F1<br />F2 = 7.0 N - 10.0 N = -3.0 N<br /><br />The negative sign indicates that the force is acting in the opposite direction to the east, which is west.<br /><br />Therefore, the correct answer is:<br /><br />3.0 N west