Soru
=(1)/(2)[(1200kg)(625-324)(m^2/s^2)+(9000kg)(400-438.2)m^2/s]
Çözüm
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Profesyonel · 6 yıl öğretmeniUzman doğrulaması
Cevap
To solve the given expression, we need to perform the calculations step by step.<br /><br />Given expression:<br />$=\frac {1}{2}[(1200kg)(625-324)(m^{2}/s^{2})+(9000kg)(400-438.2)m^{2}/s]$<br /><br />Step 1: Calculate the values inside the parentheses.<br />$(625-324) = 301$<br />$(400-438.2) = -38.2$<br /><br />Step 2: Substitute the calculated values into the expression.<br />$=\frac {1}{2}[(1200kg)(301)(m^{2}/s^{2})+(9000kg)(-38.2)m^{2}/s]$<br /><br />Step 3: Perform the multiplication inside the parentheses.<br />$(1200kg)(301)(m^{2}/s^{2}) = 363600 kg \cdot m^{2}/s^{2}$<br />$(9000kg)(-38.2)m^{2}/s = -344800 kg \cdot m^{2}/s$<br /><br />Step 4: Add the two terms inside the parentheses.<br />$=\frac {1}{2}[363600 kg \cdot m^{2}/s^{2} - 344800 kg \cdot m^{2}/s]$<br /><br />Step 5: Perform the subtraction inside the parentheses.<br />$=\frac {1}{2}[18400 kg \cdot m^{2}/s^{2}]$<br /><br />Step 6: Multiply the result by $\frac{1}{2}$.<br />$= 9200 kg \cdot m^{2}/s^{2}$<br /><br />Therefore, the final answer is $= 9200 kg \cdot m^{2}/s^{2}$.
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