Soru
run 9^2(sqrt ((3.1.10^-5.10)/(K).1.3.10^-5))^2
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Hüsam
Profesyonel · 6 yıl öğretmeniUzman doğrulaması
Cevap
To solve the given expression, let's break it down step by step:<br /><br />1. Calculate the exponentiation inside the parentheses:<br /> $9^{2} = 81$<br /><br />2. Simplify the fraction inside the square root:<br /> $\frac{3.1.10^{-5}.10}{K}.1.3.10^{-5} = \frac{3.10^{-4}}{K.3.10^{-5}} = \frac{3.10^{-4}}{3K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \frac{10^{-4}}{K.10^{-5}} = \
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