A particle starting from rest revolves with uniformly increasing speed in a clockwise circle in the cry plane The center of the circle is at the origin of an xy coordinate system Att=0 the particle is at x=0.0,y=2.9mAtt=1.0s it has made one- quarter of a revolution and is at x=y_(0),y=0.0 ) Part A Part B Determine the average velocity vector during this interval Express your answer using two significant figures. Enter the z and y components of the velocity separated by a comma. ? overrightarrow (v)_(av)=

To determine the average velocity vector, we need to find the displacement vector between the initial and final positions of the particle.<br /><br />Given:<br />Initial position: (0, 2.9) m<br />Final position: (2.9, 0) m<br />Time interval: 1.0 s<br /><br />The displacement vector is given by:<br />$\overrightarrow{d} = \overrightarrow{r}_{\text{final}} - \overrightarrow{r}_{\text{initial}} = (2.9, 0) - (0, 2.9) = (2.9, -2.9)$ m<br /><br />The average velocity vector is given by:<br />$\overrightarrow{v}_{\text{avg}} = \frac{\overrightarrow{d}}{\Delta t} = \frac{(2.9, -2.9)}{1.0} = (2.9, -2.9)$ m/s<br /><br />Therefore, the average velocity vector is:<br />$\overrightarrow{v}_{\text{avg}} = (2.9, -2.9)$ m/s