A wave is described by the function y(x,t)=(3.00cm)cos[(3.00m^-1)x+(4.00s^-1)t] What is the wavelength of this wave? Select one: 1.57 m 3.00 m 0.250 m 2.09 m 0.333 m

The correct answer is 0.333 m.<br /><br />The given wave function is in the form of $y(x,t) = A \cos(kx + \omega t)$, where $A$ is the amplitude, $k$ is the wave number, and $\omega$ is the angular frequency.<br /><br />The wave number $k$ is given by $k = 2\pi/\lambda$, where $\lambda$ is the wavelength of the wave.<br /><br />In the given function, $k = 3.00 \, \text{m}^{-1}$. To find the wavelength, we can rearrange the equation to solve for $\lambda$:<br /><br />$\lambda = \frac{2\pi}{k} = \frac{2\pi}{3.00 \, \text{m}^{-1}} \approx 0.333 \, \text{m}$<br /><br />Therefore, the wavelength of the wave is 0.333 m.