Two plates are electric potentials -15V and +35V If the separation between the plates is 2cm,the what is the electric field between them? 2500V/m 5000V/m cc 200V/m OD 500V/m

To find the electric field between the plates, we can use the formula:<br /><br />\[ E = \frac{V_2 - V_1}{d} \]<br /><br />where:<br />- \( E \) is the electric field,<br />- \( V_2 \) and \( V_1 \) are the electric potentials of the two plates,<br />- \( d \) is the separation between the plates.<br /><br />Given:<br />- \( V_2 = +35V \)<br />- \( V_1 = -15V \)<br />- \( d = 2 \text{ cm} = 0.02 \text{ m} \)<br /><br />Substitute the values into the formula:<br /><br />\[ E = \frac{35V - (-15V)}{0.02 \text{ m}} \]<br />\[ E = \frac{35V + 15V}{0.02 \text{ m}} \]<br />\[ E = \frac{50V}{0.02 \text{ m}} \]<br />\[ E = 2500 \text{ V/m} \]<br /><br />Therefore, the electric field between the plates is \( 2500 \text{ V/m} \).<br /><br />So, the correct answer is:<br />\[ \boxed{2500 \text{ V/m}} \]