A construction worker pulls a box of tools on a frictionless horizontal floor with a 100-N force applied at 37^circ above the horizontal The total mass of the box and the tools is 40 kg The magnitudes of the acceleration of the box and the normal force exerted by the floor on the box are respectively.

To find the magnitudes of the acceleration of the box and the normal force exerted by the floor on the box, we can use the principles of physics.<br /><br />Given information:<br />- The construction worker applies a 100-N force at an angle of 37° above the horizontal.<br />- The total mass of the box and the tools is 40 kg.<br />- The floor is frictionless.<br /><br />Step 1: Calculate the horizontal component of the applied force.<br />Horizontal component of the force = 100 N × cos(37°) = 80 N<br /><br />Step 2: Calculate the acceleration of the box.<br />Net force in the horizontal direction = 80 N<br />Acceleration = Net force / Mass = 80 N / 40 kg = 2 m/s²<br /><br />Step 3: Calculate the normal force exerted by the floor on the box.<br />The normal force is equal to the weight of the box, which is the mass of the box multiplied by the acceleration due to gravity.<br />Normal force = Mass × Acceleration due to gravity = 40 kg × 9.8 m/s² = 392 N<br /><br />Therefore, the magnitudes of the acceleration of the box and the normal force exerted by the floor on the box are 2 m/s² and 392 N, respectively.