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Determine which law is appropriate for solving the following problem. What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm? Law used: square :

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Determine which law is appropriate for solving the following problem.
What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm?
Law used: square  :

Determine which law is appropriate for solving the following problem. What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm? Law used: square :

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Elit · 8 yıl öğretmeni
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To determine the new volume of a gas sample when its temperature changes at constant pressure, you should use **Charles's Law**. Charles's Law states that the volume of a given mass of gas is directly proportional to its absolute temperature, provided the pressure remains constant.<br /><br />The formula for Charles's Law is:<br />\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]<br /><br />Where:<br />- \( V_1 \) is the initial volume<br />- \( T_1 \) is the initial temperature<br />- \( V_2 \) is the final volume<br />- \( T_2 \) is the final temperature<br /><br />Given:<br />- Initial volume (\( V_1 \)) = 250 mL<br />- Initial temperature (\( T_1 \)) = 300 K<br />- Final temperature (\( T_2 \)) = 350 K<br />- Pressure remains constant at 1 atm<br /><br />Using Charles's Law, we can solve for the final volume (\( V_2 \)):<br /><br />\[ \frac{250 \text{ mL}}{300 \text{ K}} = \frac{V_2}{350 \text{ K}} \]<br /><br />Cross-multiplying to solve for \( V_2 \):<br /><br />\[ V_2 = \frac{250 \text{ mL} \times 350 \text{ K}}{300 \text{ K}} \]<br />\[ V_2 = \frac{87500 \text{ mL} \cdot \text{K}}{300 \text{ K}} \]<br />\[ V_2 = 291.67 \text{ mL} \]<br /><br />So, the new volume of the gas when heated to 350 K at 1 atm is approximately 291.67 mL.<br /><br />Law used: **Charles's Law**
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