Mass box A=10grams ; Mass box B=5 grams; Mass box C -made of one A and one B How much A and B would be needed to produce 30 grams of C? square g of A; square g of B.

To solve this problem, we need to determine how many boxes of A and B are needed to produce a total mass of 30 grams for box C.<br /><br />Given:<br />- Mass of box A = 10 grams<br />- Mass of box B = 5 grams<br />- Box C is made of one A and one B, so the mass of one box C = 10 grams (A) + 5 grams (B) = 15 grams<br /><br />We want to produce 30 grams of C. Since each C is 15 grams, we need:<br /><br />\[ \frac{30 \text{ grams}}{15 \text{ grams per C}} = 2 \text{ boxes of C} \]<br /><br />Each box C consists of one A and one B. Therefore, for 2 boxes of C, we need:<br /><br />- 2 boxes of A<br />- 2 boxes of B<br /><br />Calculating the total mass:<br /><br />- Total mass of A needed: \( 2 \times 10 \text{ grams} = 20 \text{ grams} \)<br />- Total mass of B needed: \( 2 \times 5 \text{ grams} = 10 \text{ grams} \)<br /><br />Thus, to produce 30 grams of C, you would need:<br /><br />- 20 grams of A<br />- 10 grams of B<br /><br />So, the answer is:<br /><br />20 g of A; 10 g of B.