Question 1: A ball is thrown straight upward from ground level. Its initial velocity is 20ft/s Determine the maximum height it would reach. (a) 621 m (b) 20.4 m (c) 621 ft (d) 20 .4 ft

To determine the maximum height reached by the ball, we can use the kinematic equation for vertical motion:<br /><br />\[ h = \frac{v_i^2}{2g} \]<br /><br />where:<br />- \( h \) is the maximum height,<br />- \( v_i \) is the initial velocity,<br />- \( g \) is the acceleration due to gravity (approximately \( 32.2 \, \text{ft/s}^2 \)).<br /><br />Given:<br />- \( v_i = 20 \, \text{ft/s} \)<br /><br />Plugging in the values:<br /><br />\[ h = \frac{(20 \, \text{ft/s})^2}{2 \times 32.2 \, \text{ft/s}^2} \]<br />\[ h = \frac{400 \, \text{ft}^2/\text{s}^2}{64.4 \, \text{ft/s}^2} \]<br />\[ h \approx 6.21 \, \text{ft} \]<br /><br />Therefore, the maximum height the ball would reach is approximately 6.21 feet.<br /><br />The correct answer is:<br />(c) 621 ft