Select the correct answer A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approximate acceleration of the car? A. 5meters/cooond^2 6meters/second^2 C. 9meters/second^2 D. 12meters/second^2 E. 37meters/second^2

To find the acceleration of the car, we can use the equation of motion:<br /><br />\[ s = ut + \frac{1}{2}at^2 \]<br /><br />where:<br />- \( s \) is the distance covered,<br />- \( u \) is the initial velocity,<br />- \( t \) is the time taken,<br />- \( a \) is the acceleration.<br /><br />Given:<br />- \( s = 120 \) meters,<br />- \( u = 0 \) meters/second (since the car is initially at rest),<br />- \( t = 6.32 \) seconds.<br /><br />Substituting the values into the equation:<br /><br />\[ 120 = 0 \times 6.32 + \frac{1}{2}a \times (6.32)^2 \]<br /><br />\[ 120 = \frac{1}{2}a \times 39.6224 \]<br /><br />\[ 120 = 19.8128a \]<br /><br />\[ a = \frac{120}{19.8128} \]<br /><br />\[ a \approx 6.07 \text{ meters/second}^2 \]<br /><br />Therefore, the approximate acceleration of the car is:<br /><br />B. \( 6 \text{ meters/second}^2 \)