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Calculate the pressure (in atm)exerted by 5.0 moles of of a gas in a steel vessel of volume 45.7 L at 59.5^circ C

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Calculate the pressure (in atm)exerted by 5.0 moles of of a gas in a
steel vessel of volume 45.7 L at 59.5^circ C

Calculate the pressure (in atm)exerted by 5.0 moles of of a gas in a steel vessel of volume 45.7 L at 59.5^circ C

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To calculate the pressure exerted by the gas, we can use the ideal gas law equation:<br /><br />PV = nRT<br /><br />Where:<br />P = Pressure (in atm)<br />V = Volume (in L)<br />n = Number of moles<br />R = Ideal gas constant (0.0821 L·atm/mol·K)<br />T = Temperature (in K)<br /><br />Given information:<br />- Number of moles (n) = 5.0 moles<br />- Volume (V) = 45.7 L<br />- Temperature (T) = 59.5°C<br /><br />Step 1: Convert the temperature from Celsius to Kelvin.<br />T = 59.5°C + 273.15 = 332.65 K<br /><br />Step 2: Substitute the given values into the ideal gas law equation and solve for the pressure (P).<br />PV = nRT<br />P = (nRT) / V<br />P = (5.0 moles × 0.0821 L·atm/mol·K × 332.65 K) / 45.7 L<br />P = 1.22 atm<br /><br />Therefore, the pressure exerted by the gas in the steel vessel is 1.22 atm.
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