strings of length L_(1)=1.1 m and L_(2)=1.7 m. as shown in Aball of mass 070 kg is attached to a vertical post by (Figure 1). The ball is set moving in a horizontal circle Part B Determine the ter tension in the L_(1) string if the ball is moving at twice the speed found in part A Express your answer with the appropriate units. ? F_(ri)=Value Units

To determine the tension in the $L_{1}$ string when the ball is moving at twice the speed found in part A, we can use the formula for centripetal force:<br /><br />$F_{c} = \frac{mv^2}{r}$<br /><br />where $m$ is the mass of the ball, $v$ is the velocity of the ball, and $r$ is the radius of the circular path.<br /><br />Given that the mass of the ball is 0.70 kg and the radius of the circular path is $L_{1} = 1.1$ m, we can substitute these values into the formula:<br /><br />$F_{c} = \frac{(0.70 \, \text{kg}) \times (2v)^2}{1.1 \, \text{m}}$<br /><br />Simplifying the expression, we get:<br /><br />$F_{c} = \frac{4(0.70 \, \text{kg})v^2}{1.1 \, \text{m}}$<br /><br />Therefore, the tension in the $L_{1}$ string when the ball is moving at twice the speed found in part A is:<br /><br />$F_{ri} = \frac{4(0.70 \, \text{kg})v^2}{1.1 \, \text{m}}$<br /><br />The units for the tension will be in Newtons (N).