Consider the system shown in the figure (Exgure 1) Block A has weight w_(A) and block B has weight wB Once block B is set into downward motion it descends at a constant speed Assume that the mass and friction of the pulloy are negligible Part A Calculate the coefficient of kinetic friction is between block A and the table top Express your answer in terms of some or all of the variables w_(A) subscript A), wp, and g (the acceleration due to gravity). View Available Hint(s) square sqrt [square ](square ) Asum phi ? x^a x_(b) √x Vx x x xcdot 10^n D mu =(w_(b))/(w_(a))

To calculate the coefficient of kinetic friction between block A and the table top, we need to consider the forces acting on block A.<br /><br />The force of kinetic friction (F_k) is given by the equation:<br /><br />F_k = μ * N<br /><br />where μ is the coefficient of kinetic friction and N is the normal force acting on block A.<br /><br />Since block A is in equilibrium and moving at a constant speed, the net force acting on it is zero. Therefore, the force of kinetic friction is equal to the force of gravity acting on block B.<br /><br />The force of gravity acting on block B is given by:<br /><br />F_g = w_B * g<br /><br />where w_B is the weight of block B and g is the acceleration due to gravity.<br /><br />Since the mass and friction of the pulley are negligible, the force of kinetic friction is equal to the force of gravity acting on block B:<br /><br />F_k = F_g<br /><br />Substituting the values, we have:<br /><br />μ * N = w_B * g<br /><br />The normal force (N) acting on block A is equal to the weight of block A:<br /><br />N = w_A * g<br /><br />Substituting this value into the equation, we get:<br /><br />μ * w_A * g = w_B * g<br /><br />Simplifying the equation, we find:<br /><br />μ = w_B / w_A<br /><br />Therefore, the coefficient of kinetic friction between block A and the table top is given by:<br /><br />μ = w_B / w_A<br /><br />This expression represents the coefficient of kinetic friction in terms of the weights of blocks A and B, and the acceleration due to gravity.