If the density of lead is 11.34g/cm^3 how many atoms are in a lead with a volume of 40cm^3 a. 1.32times 10^24 b. 1.16times 10^22 C. 1.16times 10^23 d. 6.6times 10^23 e. 1.32times 10^23

To find the number of atoms in a lead with a volume of 40 cm³, we need to use the given density of lead, which is 11.34 g/cm³.<br /><br />First, we can calculate the mass of the lead using the formula:<br /><br />mass = density × volume<br /><br />mass = 11.34 g/cm³ × 40 cm³<br />mass = 453.6 g<br /><br />Next, we need to find the number of moles of lead in the given mass. We can use the molar mass of lead, which is 207.2 g/mol.<br /><br />moles of lead = mass / molar mass<br />moles of lead = 453.6 g / 207.2 g/mol<br />moles of lead ≈ 2.18 mol<br /><br />Finally, we can calculate the number of atoms using Avogadro's number, which is 6.022 × 10²³ atoms/mol.<br /><br />number of atoms = moles of lead × Avogadro's number<br />number of atoms = 2.18 mol × 6.022 × 10²³ atoms/mol<br />number of atoms ≈ 1.32 × 10²³ atoms<br /><br />Therefore, the correct answer is option e. $1.32\times 10^{23}$