Question 5. An electrical heater having a resistance of 2Omega is connected to a direct source of 10V Find a.The power of the electric heater. (5p) b. Find the electrical energy dissipated in 3 seconds. (5p)

a. The power of the electric heater can be calculated using the formula:<br /><br />\[ P = \frac{V^2}{R} \]<br /><br />where \( P \) is the power, \( V \) is the voltage, and \( R \) is the resistance.<br /><br />Given that the resistance \( R \) is \( 2\Omega \) and the voltage \( V \) is \( 10V \), we can substitute these values into the formula:<br /><br />\[ P = \frac{10^2}{2} = \frac{100}{2} = 50W \]<br /><br />Therefore, the power of the electric heater is \( 50W \).<br /><br />b. The electrical energy dissipated in 3 seconds can be calculated using the formula:<br /><br />\[ E = P \times t \]<br /><br />where \( E \) is the energy, \( P \) is the power, and \( t \) is the time.<br /><br />Given that the power \( P \) is \( 50W \) and the time \( t \) is \( 3 \) seconds, we can substitute these values into the formula:<br /><br />\[ E = 50 \times 3 = 150J \]<br /><br />Therefore, the electrical energy dissipated in 3 seconds is \( 150J \).