If it takes total work W to give an object a speed vand kinetic energy K, starting from rest, what will be the object's speed (in terms of v)if we do twice as much work on it, again starting from rest? Round off your result to 1 decimal place.

## Step 1<br />The problem involves the concept of kinetic energy and work done. The kinetic energy (K) of an object is given by the formula:<br />### \(K = \frac{1}{2}mv^2\)<br />where \(m\) is the mass of the object and \(v\) is its velocity.<br /><br />## Step 2<br />The work done (W) on an object is equal to the change in its kinetic energy. This is based on the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.<br /><br />## Step 3<br />In this problem, we are given that the total work done (W) gives the object a speed \(v\). If we do twice as much work on it, the new speed will be the square root of the ratio of the new work done to the original work done.<br /><br />## Step 4<br />The new work done is twice the original work done, so the new speed will be the square root of 2 times the original speed.