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((1)/(2))^-2+((3)/(2))^2-((1)/(5))^-1=?

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((1)/(2))^-2+((3)/(2))^2-((1)/(5))^-1=?

((1)/(2))^-2+((3)/(2))^2-((1)/(5))^-1=?

Çözüm

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Usta · 5 yıl öğretmeni
Uzman doğrulaması

Cevap

To solve this expression, we need to perform the operations step by step:<br /><br />1. Simplify the fractions:<br /> - $\frac{1}{2}$ remains as $\frac{1}{2}$.<br /> - $\frac{2}{2}$ simplifies to $1$.<br /> - $\frac{3}{2}$ remains as $\frac{3}{2}$.<br /> - $(\frac{1}{5})^{-1}$ is the reciprocal of $\frac{1}{5}$, which is $5$.<br /><br />2. Perform the addition and subtraction:<br /> - $(\frac{1}{2}) + 1 + (\frac{3}{2}) - 5$<br /> - $\frac{1}{2} + 1 + \frac{3}{2} - 5$<br /> - $\frac{1}{2} + \frac{3}{2} = 2$<br /> - $2 + 1 = 3$<br /> - $3 - 5 = -2$<br /><br />Therefore, the correct answer is $-2$.
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