Calculate the mean for samples for which the sample size and sum x are given below. a n=10,sum x=84 b n=16,sum x=352 c n=45,sum x=35 d. n=18,sum x=238 a. bar (x)= (Round to two decimal places as needed.)

To calculate the mean for samples, we can use the formula:<br /><br />$\bar{x} = \frac{\sum x}{n}$<br /><br />where $\sum x$ is the sum of the data values and $n$ is the sample size.<br /><br />Let's calculate the mean for each of the given samples:<br /><br />a. For $n=10,\sum x=84$, we can substitute these values into the formula:<br /><br />$\bar{x} = \frac{84}{10} = 8.4$<br /><br />Therefore, the mean for this sample is 8.4.<br /><br />b. For $n=16,\sum x=352$, we can substitute these values into the formula:<br /><br />$\bar{x} = \frac{352}{16} = 22$<br /><br />Therefore, the mean for this sample isc. For $n=45,\sum x=35$, we can substitute these values into the formula:<br /><br />$\bar{x} = \frac{35}{45} = 0.78$<br /><br />Therefore, the mean for this sample is 0.78.<br /><br />d. For $n=18,\sum x=238$, we can substitute these values into the formula:<br /><br />$\bar{x} = \frac{238}{18} = 13.22$<br /><br />Therefore, the mean for this sample is 13.22.<br /><br />In summary, the means for the given samples are:<br />a. $\bar{x} = 8.4$<br />b. $\bar{x} = 22$<br />c. $\bar{x} = 0.78$<br />d. $\bar{x} = 13.22$