Kimya Ödev Yardımı

QuetionAI‘nin kimya problemi çözücüsü, temel kimyasal reaksiyonları ve denklemleri kullanıcılar için gerçek zamanlı olarak özetleyebilen ve zayıf bir temele sahip öğrencilerin bile kimyada kolayca uzmanlaşabilmesi için güçlü bir öğrenme sistemine sahip olan bir ortaokul kimya ders aracıdır.

Artık periyodik tablonun temel özellikleri hakkında endişelenmenize gerek yok. Burada her elemente karşılık gelen kimyasal reaksiyonlara ve reaksiyon prensiplerine kolaylıkla ulaşabilirsiniz. Moleküllerin ve atomların orijinal yapısını, görülebilen makroskobik olaylardan çıkarmak, her zaman savunduğumuz bir kimya araştırma tekniğidir.

The atomic number of the element which does not usually form compounds because its outermost shell is full is: 20 18 8 16 19

Complete the sentence. Select all that apply. In the vertical columns of the periodic table: the number of shells Increases from top to bottom all the physical properties are identical atomic weight Increases from top to bottom outer shell electrons increase from top to bottom

Results: The formulation involved mixing castor oil (oil phase)with an aqueous phase containing lemon syrup. Since Tween 80 (hydrophilic) has a higher HLB value than Span 80 (lipophilic), we obtained an emulsion that is more likely to be an oil-in-water (o/w) emulsion. Upon adding the aqueous phase (lemon syrupand Tween 80)to the oil phase (castor oil and Span 80),the mixture began to emulsify, and a smooth uniform consistency was observed. The emulsion appeared creamy and stable after the phases were combined and stirred. The final emulsion appeared opaque, with a slightly creamy texture, consistent with the formation of an oil-in-water (o/w) emulsion. Rx / Castor oil __ 12.5ml Tween80 __ 1.13g Span80 __ 0.115g Lemon syrup __ 12.5ml Discussion: The use of tale in thelemon syrupprocedure helpsremoveany undissolve particles, ensuringa clear syrup Gradually, adding water and filtering ensures proper dissolution of ingredients like sucrose and citric acid. The dissolution process without heating prevents degradation of sensitive ingredients. Concerning the castor oil emulsion, the blendingof Span 80 and Tween 80 is based on their HLB values,which are chosen to form a stable oil -in-water emulsion. The continuous stirringduring the addition of theaqueous phase is essential to form a stable emulsion without phase separation. No phase separation was noted during the stirring process, indicating successful emulsion formation. The final emulsifier concentration is crucial to ensure the emulsion remains stable and does not separate over time. The emulsion remained stable with no signs of phase separationor coalescenceafter several hours of observation. No visible degradation, such as oil droplets separating from the aqueous phase.was observed, suggesting that the emulsifier blend was effective in maintaining the emulsion's stability. The opacity of the emulsion was due to the dispersion of the oil phase within the aqueous phase, which is characteristic of o/wemulsions. The presence of the lemon syrup contributed to the cloudy appearance. If the emulsion type was water-in-oil (w/o) , the reverse process would be required, where theaqueousphase would be slowly added to the oil phase. The aqueous phase should be heated up to 70-80^circ C

7. Esit mol sayili CH_(4) ve N_(2)O gaz karişimi toplam 180 gram gelmektedir. Buna gore, karişimdaki CH_(4) gazi normal kosullarda kaç litredir? H:1g/mol,C:12g/mol,N:14g/mol,O:16g/mol) A) 22,4 B) 44,8 C) 67,2 D) 112 E) 134,4 8. 3,6.N_(A) akb kütlesine sahip H_(2)O bilesiginde kaç gram H atomu bulunur? (H:1g/mol,O:16g/mol,N_(A): Avogadro sayisi) A) 0,1 B) 0,2 C) 0,3 D) 0,4 E) 0,5 9. 1 tane {}^27Al atomu ile ilgili, 1. 27 gramdir. II. 27 akb'dir. III. 27/6,02.10^23 gramdir Hadelerinden hangilerl yanliştir? (Avogadro sayisi: 6,02.10^23) A) Yalniz I B) Yalniz III C) I ve II D) I ve III E) II ve III

Ninyamin Temer Kanuman 1. Esit kütlelerde alinan; I. N_(2)O_(3) II. CaCl_(2) III. C_(2)H_(6) maddelerinin mol sayilarimin büyldkton kücüge dogru siralanişu asağidakilerden hangisidir? (H:1g/mol,C:12g/mol,N:14g/mol,O:16g/mol Cl:35,5g/mol, Ca:40g/mol A) 1gt Vert gt Vert vert B) 1gt Vert vert gt 1vert IIgt 1gt III D) IIIgt Igt II E) Vert vert gt Vert gt vert 2. Agağidakilerdon hangisinde oksijenin kütlesi en bũ- yüktür? (O:16g/mol Avogadro sayisi: 6,02.10^23 A) 1 tane oksijen atomu B) 8 akb oksijen atomu C) 1 tane oksijen molek0lu D) 1 mol oksijen molektila E) 1 gram oksijen atomu 3. Kukurt ve oksijenden olusan 0,5 mollik kanşim 12 gramdir. Buna gore, karisimin kaç grami oksijendir? (O:16g/mol,S:32g/mol) A) 2 B) 4 C) 8 D) 16 E) 32