a. Asagidaki ifadelerin esitini yaziniz. c. sqrt (a-sqrt (b))cdot sqrt (a+sqrt (b)) a. sqrt (5)cdot sqrt (6) sqrt [3](9)cdot sqrt [3](81) c. (sqrt [5](125))/(sqrt [5](5)) d. (sqrt [3](16^2))/(sqrt [3](2^-2)) e. (sqrt (frac (18)/(7)))(sqrt ((14)/(9)))

a. $\sqrt {5}\cdot \sqrt {6} = \sqrt {30}$<br /><br />c. $\sqrt {a-\sqrt {b}}\cdot \sqrt {a+\sqrt {b}} = \sqrt {(a-\sqrt {b})(a+\sqrt {b})} = \sqrt {a^2 - b}$<br /><br />b. $\sqrt [3]{9}\cdot \sqrt [3]{81} = \sqrt [3]{729} = 9$<br /><br />c. $\frac {\sqrt [5]{125}}{\sqrt [5]{5}} = \frac {\sqrt [5]{5^3}}{\sqrt [5]{5}} = \sqrt [5]{5^2} = 5^{\frac {2}{5}}$<br /><br />d. $\frac {\sqrt [3]{16^{2}}}{\sqrt [3]{2^{-2}}} = \frac {\sqrt [3]{256}}{\sqrt [3]{\frac {1}{4}}} = \frac {\sqrt [3]{256}}{\frac {1}{\sqrt [3]{4}}} = \sqrt [3]{256}\cdot \sqrt [3]{4} = \sqrt [3]{1024} = 4$<br /><br />e. $\frac {\sqrt {\frac {18}{7}}}{\sqrt {\frac {14}{9}}} = \frac {\sqrt {\frac {18}{7}}}{\sqrt {\frac {14}{9}}} = \frac {\sqrt {\frac {18}{7}}}{\frac {\sqrt {14}}{\sqrt {9}}} = \frac {\sqrt {\frac {18}{7}}}{\frac {\sqrt {14}}{3}} = \frac {3\sqrt {\frac {18}{7}}}{\sqrt {14}} = \frac {3\sqrt {18}}{\sqrt {7}\sqrt {14}} = \frac {3\sqrt {18}}{\sqrt {98}} = \frac {3\sqrt {18}}{7\sqrt {2}} = \frac {3\sqrt {9}\sqrt {2}}{7\sqrt {2}} = \frac {3\cdot 3\sqrt {2}}{7\sqrt {2}} = \frac {9\sqrt {2}}{7\sqrt {2}} = \frac {9}{7}$